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-4y^2-21y-5=0
a = -4; b = -21; c = -5;
Δ = b2-4ac
Δ = -212-4·(-4)·(-5)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-19}{2*-4}=\frac{2}{-8} =-1/4 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+19}{2*-4}=\frac{40}{-8} =-5 $
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